\(20\%.x+\dfrac{5}{8}x.0,5=\dfrac{11}{26}\)
help me HELP ME
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\(\dfrac{4}{x-3}=\dfrac{8}{y-6}=\dfrac{20}{z-15}\)
\(\Rightarrow\dfrac{x-3}{4}=\dfrac{y-6}{8}=\dfrac{z-15}{20}\)
\(\Rightarrow\dfrac{x}{4}-\dfrac{3}{4}=\dfrac{y}{8}-\dfrac{3}{4}=\dfrac{z}{20}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{x}{4}=\dfrac{y}{8}=\dfrac{z}{20}\)
Đặt: \(\dfrac{x}{4}=\dfrac{y}{8}=\dfrac{z}{20}=k\Leftrightarrow\left\{{}\begin{matrix}x=4k\\y=8k\\z=20k\end{matrix}\right.\)
Thay vào đk đề bài: \(640k^3=640\Leftrightarrow k=1\)
Vậy \(\left\{{}\begin{matrix}x=4\\y=8\\z=20\end{matrix}\right.\)
a: \(A=\dfrac{1.3-2.6}{2.6}-\dfrac{5}{6}:2=\dfrac{-1}{2}-\dfrac{5}{12}=\dfrac{-11}{12}\)
\(B=\left(\dfrac{47}{8}-\dfrac{9}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}=\dfrac{47-18-4}{8}\cdot\dfrac{26}{75}=\dfrac{25}{75}\cdot\dfrac{26}{8}=\dfrac{13}{12}\)
b: Để A<x<B thì -11/12<x<13/12
mà x là số nguyên
nên \(x\in\left\{0;1\right\}\)
a: =>\(-\dfrac{6+x}{2}-\dfrac{3}{2}=2\)
=>-x-6-3=4
=>-x-9=4
=>-x=5
hay x=-5
b: =>(x+1)2=16
=>x+1=4 hoặc x+1=-4
=>x=3 hoặc x=-5
c: \(\Leftrightarrow\left(\dfrac{x-2}{27}-1\right)+\left(\dfrac{x-3}{26}-1\right)+\left(\dfrac{x-4}{25}-1\right)+\left(\dfrac{x-5}{24}-1\right)+\left(\dfrac{x-44}{5}+3\right)=0\)
=>x-29=0
hay x=29
\(\dfrac{x+2}{0,5}=\dfrac{2x+1}{2}\)
\(\Leftrightarrow\left(x+2\right).2=\left(2x+1\right).0,5\)
\(\Leftrightarrow2x+4=x+0,5\)
\(\Leftrightarrow x=-3,5\)
Vậy...
\(\dfrac{x+2}{0,5}=\dfrac{2x+1}{2}\)
\(\Leftrightarrow\dfrac{4.\left(x+2\right)}{2}=\dfrac{2x+1}{2}\)
\(\Rightarrow4x+8=2x+1\)
\(\Leftrightarrow4x-2x=1-8\)
\(\Leftrightarrow2x=-7\)
\(\Leftrightarrow x=\dfrac{-7}{2}\)
Vậy \(x=\dfrac{-7}{2}\)
\(\dfrac{6}{13}.\dfrac{8}{7}+\dfrac{6}{13}.\dfrac{9}{7}-\dfrac{3}{13}.\dfrac{6}{7}=\dfrac{6}{13}.\left(\dfrac{8}{7}+\dfrac{9}{7}\right)-\dfrac{3}{13}.\dfrac{6}{7}=\dfrac{6}{13}.\dfrac{17}{7}-\dfrac{3}{13}.\dfrac{6}{7}=\dfrac{102}{91}-\dfrac{18}{91}=\dfrac{12}{13}\)
a, \(\dfrac{9}{18}-\dfrac{-7}{12}+\dfrac{13}{32}\)
\(=\dfrac{1}{2}+\dfrac{7}{12}+\dfrac{13}{32}\)
\(=\dfrac{13}{12}+\dfrac{13}{32}=\dfrac{143}{96}\)
b, \(\dfrac{5}{-8}+\dfrac{14}{39}-\dfrac{6}{10}\)
\(\dfrac{-5}{8}+\dfrac{14}{39}-\dfrac{3}{5}\)
\(=\dfrac{-5}{8}-\dfrac{3}{5}+\dfrac{14}{39}\)
\(=\dfrac{-49}{40}+\dfrac{14}{39}=\dfrac{-1351}{1560}\)
= 28/15 . 3/4 - ( 11/20 + 1/4 ) : 7/3
= 28/15 . 3/4 - 4/5 : 7/3
= 7/5 - 12/35
= 37/35
= \(\dfrac{28}{15}\) . \(\dfrac{3}{4}\) - (\(\dfrac{11}{20}\) + \(\dfrac{1}{4}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - (\(\dfrac{11}{20}\) + \(\dfrac{5}{20}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) x \(\dfrac{3}{7}\)
= \(\dfrac{7}{5}\) - \(\dfrac{12}{35}\)
= \(\dfrac{49}{35}\) - \(\dfrac{12}{35}\)
= \(\dfrac{37}{35}\)