(3/20 + 1/2 - 1/15) × 12/49
Mình ngu Toán nên....
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\(\frac{1.3.5+2.6.10+4.12.20+7.21.35}{1.5.7+2.10.14+4.20.28+7.35.49}\)
\(=\frac{1.3.5\left(1+2+4+7\right)}{1.5.7\left(1+2+7+7\right)}=\frac{1.3.5}{1.5.7}=\frac{15}{35}=\frac{3}{7}\)
\(\frac{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+7\cdot21\cdot35}{1\cdot5\cdot7+2\cdot10\cdot14+4\cdot20\cdot28+7\cdot35\cdot49}\)
\(=\)\(\frac{1\cdot3\cdot5\cdot\left(1+2+4+7\right)}{1\cdot5\cdot7\cdot\left(1+2+7+7\right)}\)
\(=\frac{1\cdot3\cdot5}{1\cdot5\cdot7}\)\(=\frac{15}{35}=\frac{3}{7}\)
bn vội quá viết nhầm lun kìa
hj hj chúc bn làm bài tốt nha
\(A=\left(\frac{1}{10}-1\right)\left(\frac{1}{11}-1\right)\left(\frac{1}{12}-1\right)...\left(\frac{1}{99}-1\right)\left(\frac{1}{100}-1\right)\)
\(=\frac{-9}{10}.\frac{-10}{11}.\frac{-11}{12}...\frac{-98}{99}.\frac{-99}{100}\)
\(=-\frac{9.10.11....98.99}{10.11.12...99.100}=-\frac{9}{100}\)
\(\left(\dfrac{3}{20}+\dfrac{1}{2}-\dfrac{1}{15}\right)\times\dfrac{12}{49}\)
\(=\left(\dfrac{3}{20}+\dfrac{10}{20}-\dfrac{1}{15}\right)\times\dfrac{12}{49}\)
\(=\left(\dfrac{13}{20}-\dfrac{1}{15}\right)\times\dfrac{12}{49}\)
\(=\left(\dfrac{39}{60}-\dfrac{4}{60}\right)\times\dfrac{12}{49}\)
\(=\dfrac{35}{60}\times\dfrac{12}{49}\)
\(=\dfrac{35\times12}{60\times49}\)
\(=\dfrac{1}{7}\)
_HT_
= (13/20-1/15)x12/49
=48/60x12/49
=576/2940