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7 tháng 4 2022

a)\(\dfrac{56}{70}=\dfrac{56:14}{70:14}=\dfrac{4}{5}\)

b)\(\dfrac{-120}{86}=\dfrac{-120:2}{86:2}=-\dfrac{60}{43}\)

c)\(\dfrac{915+85}{1017-117}=\dfrac{1000}{900}=\dfrac{10}{9}\)

d)\(\dfrac{3838}{5454}=\dfrac{19}{27}\)

7 tháng 4 2022

a) \(\dfrac{56}{70}=\dfrac{4}{5}\)

\(b,-\dfrac{120}{86}=-\dfrac{60}{43}\)

\(c,\dfrac{10}{9}\)

\(d,\dfrac{19}{27}\)

Giải:

a) \(\dfrac{5^3.90.4^3}{25^2.3^2.2^{13}}\) 

\(=\dfrac{5^3.5.3^2.2.\left(2^2\right)^3}{\left(5^2\right)^2.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2.2^6}{5^4.3^2.2^{13}}\) 

\(=\dfrac{5^4.3^2.2^7}{5^4.3^2.2^{13}}\) 

\(=\dfrac{1}{2^6}=\dfrac{1}{64}\) 

b) \(\dfrac{15^2.16^4-15^3.16^3}{12^2.20^3-20^2.12^3}\) 

\(=\dfrac{15^2.16^3.16-15^2.16^3.15}{12^2.20^2.20-20^2.12^2.12}\) 

\(=\dfrac{15^2.16^3.\left(16-15\right)}{12^2.20^2.\left(20-12\right)}\) 

\(=\dfrac{\left(3.5\right)^2.\left(2^4\right)^3.1}{\left(3.2^2\right)^2.\left(2^2.5\right)^2.8}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.\left(2^2\right)^2.\left(2^2\right)^2.5^2.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^4.2^4.2^3}\) 

\(=\dfrac{3^2.5^2.2^{12}}{3^2.5^2.2^{11}}\) 

\(=2\) 

c) \(\dfrac{2.3+4.6+14.21}{3.5+6.10+21.35}\) 

\(=\dfrac{2.3+2.3.2.2+2.3.7.7}{3.5+3.5.2.2+3.5.7.7}\) 

\(=\dfrac{2.3+2.3.4+2.3.49}{3.5+3.5.4+3.5.49}\) 

\(=\dfrac{2.3.\left(1+4+49\right)}{3.5.\left(1+4+49\right)}\) 

\(=\dfrac{2.3}{3.5}\) 

\(=\dfrac{2}{5}\) 

Chúc bạn học tốt!

24 tháng 2 2023

mình hứa sẽ tick

24 tháng 2 2023

= 2/5 + 1/5 + 1/5

= 4/5

b. = 2/7 + 4/7 + 5/21

= 6/21 + 12/21 + 5/21

= 23/21

HT

\(\dfrac{60}{72}=\dfrac{60:12}{72:12}=\dfrac{5}{6}\\ \dfrac{70}{95}=\dfrac{70:5}{95:5}=\dfrac{14}{19}\\ \dfrac{150}{360}=\dfrac{150:30}{360:30}=\dfrac{5}{12}\)

1 tháng 4 2021

\(\dfrac{60}{72}=\dfrac{5}{6}\)

\(\dfrac{70}{95}=\dfrac{14}{19}\)

\(\dfrac{150}{360}=\dfrac{5}{12}\)

B=4/9(1/3+2/3)+14/9=4/9+14/9=2/1

14 tháng 5 2022

B = 2/1 = 2

a:

Sửa đề: \(\dfrac{n+1}{2n+3}\)

Gọi d=ƯCLN(n+1;2n+3)

=>2n+2-2n-3 chia hết cho d

=>-1 chia hết cho d

=>d=1

=>ĐPCM

b: Gọi d=ƯCLN(4n+8;2n+3)

=>4n+8-4n-6 chia hết cho d

=>2 chia hêt cho d

=>d=1

=>ĐPCM

c: Gọi d=ƯCLN(3n+2;5n+3)

=>15n+10-15n-9 chia hết cho d

=>1 chia hết cho d

=>d=1

=>ĐPCM

9 tháng 5 2021

\(a.\)

\(\dfrac{3}{10}:\left(-\dfrac{2}{3}\right)=\dfrac{3}{10}\cdot\dfrac{-3}{2}=-\dfrac{9}{20}\)

\(b.\)

\(\left(-\dfrac{7}{12}\right):\left(-\dfrac{5}{6}\right)=\left(-\dfrac{7}{12}\right)\cdot\left(-\dfrac{6}{5}\right)=\dfrac{\left(-7\right)\cdot\left(-6\right)}{12\cdot5}=\dfrac{7}{10}\)

\(c.\)

\(\left(-15\right):-\dfrac{9}{10}=\left(-15\right)\cdot-\dfrac{10}{9}=\dfrac{150}{9}=\dfrac{50}{3}\)

a) \(\dfrac{3}{10}:\dfrac{-2}{3}=\dfrac{3}{10}.\dfrac{-3}{2}=\dfrac{3.-3}{10.2}=\dfrac{-9}{20}\) 

b) \(\dfrac{-7}{12}:\dfrac{-5}{6}=\dfrac{-7}{12}.\dfrac{-6}{5}=\dfrac{-7.-6}{12.5}=\dfrac{7}{10}\) 

c)\(-15:\dfrac{-9}{10}=-15.\dfrac{-10}{9}=\dfrac{-15.-10}{9}=\dfrac{50}{3}\)