giup mik voi a
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19,My father used to smoke
20,The cake is cleverly cut by her
21,Ba offered Mai to dance
22,My father told us that he was very happy then
1. what he often did on Sunday mornings.
2. I must finish the report by ten o'clock
3. was hot so we turned on the air conditional
4. my favourite band wouldn't leave here tomorrow
5. have you learned English?
6. Tung if he liked dancing.
7. so she got good grades in her exam
8. he didn't make such terrible mistakes
9. Tom what he would do after that class.
1: Ta có: \(3\left(x+5\right)-2\left(4-3x\right)=7\)
\(\Leftrightarrow3x+15-8+6x=7\)
\(\Leftrightarrow9x=14\)
hay \(x=\dfrac{14}{9}\)
2: Ta có: \(x\left(7-2x\right)+2x\left(x-2\right)=15\)
\(\Leftrightarrow7x-2x^2+2x^2-4x=15\)
\(\Leftrightarrow3x=15\)
hay x=5
3: Ta có: \(2x\left(9x-4\right)-9x\left(2x-3\right)=-38\)
\(\Leftrightarrow18x^2-8x-18x^2+27x=-38\)
\(\Leftrightarrow19x=-38\)
hay x=-2
7: Ta có: \(\left(x-5\right)\left(x+5\right)-\left(x-5\right)^2=30\)
\(\Leftrightarrow x^2-5-x^2+10x-25=30\)
\(\Leftrightarrow10x=60\)
hay x=6
8: Ta có: \(\left(x+2\right)\left(x-2\right)+8=\left(x-1\right)^2\)
\(\Leftrightarrow x^2-4+8=x^2-2x+1\)
\(\Leftrightarrow-2x=3\)
hay \(x=-\dfrac{3}{2}\)
`@` `\text {Ans}`
`\downarrow`
`a)`
`-3x - 3/4 = 6/5`
`=> -3x = 6/5 + 3/4`
`=> -3x = 39/20`
`=> x = 39/20 \div (-3)`
`=> x = -13/20`
Vậy, `x=-13/20`
`b)`
`1/7 - 3/5x = 3/5`
`=> 3/5x = 1/7 - 3/5`
`=>3/5x = -16/35`
`=> x = -16/35 \div 3/5`
`=> x = -16/21`
`c)`
`3/7 - 1/2x = 5/3`
`=> 1/2x = 3/7 - 5/3`
`=> 1/2x = -26/21`
`=> x = -26/21 \div 1/2`
`=> x = -52/21`
Vậy, `x = -52/21`
`d)`
`-2/3x + 2 = 3/4`
`=> -2/3x = 3/4 - 2`
`=> -2/3x = -5/4`
`=> x = -5/4 \div (-2/3)`
`=> x = 15/8`
Vậy, `x=15/8.`
8 It took me 3 hours to do these exercise
9 Many years ago, my village used to be very poor
10 Mary last met him 5 years ago
11 Would you mind giving me a hand
12 There used to be many old buildings in this city
13 When were they married
14 I started learning Japanese 2 years ago
15 Jack used to be a good student
16 My sister used to buy all her clothes in Henry's
17 Braille is reading system for the blind
a: Xét ΔBAE và ΔBDE có
BA=BD
\(\widehat{ABE}=\widehat{DBE}\)
BE chung
Do đó: ΔBAE=ΔBDE
b: Ta có: ΔBAE=ΔBDE
nên \(\widehat{BAE}=\widehat{BDE}=90^0\)
hay ED\(\perp\)BC
c: Xét ΔAKE vuông tại A và ΔDCE vuông tại D có
EA=ED
\(\widehat{AEK}=\widehat{DEC}\)
Do đó: ΔAKE=ΔDCE
Suy ra: EK=EC
hay ΔEKC cân tại E
lỗi r bn
???