Tìm x : ba phần tư nhân x trừ năm phần ba nhân x = bay phần muoi hai
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\(\frac{35}{6}+X=\frac{3}{4}\times5\frac{1}{2}\)
\(\frac{35}{6}_{ }+X=\frac{33}{8}\)
\(X=\frac{33}{8}-\frac{35}{6}\)
\(X=\frac{-41}{24}\)
4/5 x 3/4 - 3/10
= 12/20 - 3/10
= 12/20 - 6/20
= 6/20
= 3/10
\(\frac{15}{a}\cdot\frac{2}{3}\cdot\frac{3}{2}=\frac{5}{4}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}:\frac{3}{2}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{4}\cdot\frac{2}{3}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{10}{12}\)
\(\frac{15}{a}\cdot\frac{2}{3}=\frac{5}{6}\)
\(\frac{15}{a}=\frac{5}{6}:\frac{2}{3}\)
\(\frac{15}{a}=\frac{5}{6}\cdot\frac{3}{2}\)
\(\frac{15}{a}=\frac{15}{12}\)
Ta có: \(\frac{15}{a}=\frac{15}{12}\)
Mặt khác: 15 = 15 => a = 12
Vậy a tìm được bằng 12
\(\frac{3}{4}x\frac{5}{6}-\frac{1}{6}=\frac{11}{24}\)
\(4\frac{8}{5}-\frac{2}{3}=\frac{28}{5}-\frac{2}{3}=\frac{74}{15}\)
X x 2/7 - 2/3 = 1/2
X x 2/7 = 1/2 + 2/3
X x 2/7 = 7/6
X = 7/6 : 2/7
X = 49/12
Ta có
a/ 1/3x - 3/4x = 5/12 1/4x + 3/4 +x =7/8
x(1/3-3/4)=5/12 2x=7/8
-5/12x=5/12 x=7/8 : 2 =7/16
x=5/12 : -5/12
x=-1
a) \(\frac{2}{3}x-\frac{1}{2}x=\frac{5}{12}\)
\(x\left(\frac{2}{3}-\frac{1}{2}\right)=\frac{5}{12}\)
\(x\left(\frac{4}{6}-\frac{3}{6}\right)=\frac{5}{12}\)
\(\frac{1}{6}x=\frac{5}{12}\)
\(x=\frac{5}{12}:\frac{1}{6}=\frac{5}{2}\)
b) \(25\%x+\frac{3}{4}x+x=\frac{7}{8}\)
\(x\left(25\%+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(\frac{1}{4}+\frac{3}{4}+1\right)=\frac{7}{8}\)
\(x\left(1+1\right)=\frac{7}{8}\)
\(2x=\frac{7}{8}\)
\(x=\frac{7}{8}:2=\frac{7}{16}\)
\(\frac{3}{4}\times x+\frac{5}{3}\times x=\frac{7}{12}\)
\(\left(\frac{3}{4}+\frac{5}{3}\right)\times x=\frac{7}{12}\)
\(\frac{29}{12}\times x=\frac{7}{12}\)
\(x=\frac{7}{12}\div\frac{29}{12}\)
\(x=\frac{7}{29}\)
-11
7