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\(\frac{35}{6}+X=\frac{3}{4}\times5\frac{1}{2}\)
\(\frac{35}{6}_{ }+X=\frac{33}{8}\)
\(X=\frac{33}{8}-\frac{35}{6}\)
\(X=\frac{-41}{24}\)
\(\frac{3}{4}x\frac{5}{6}-\frac{1}{6}=\frac{11}{24}\)
\(4\frac{8}{5}-\frac{2}{3}=\frac{28}{5}-\frac{2}{3}=\frac{74}{15}\)
1/3 + 5/2 + 10/6 = 4/12 + 30/12 + 20/12 = 54/12 = 27/6
\(\dfrac{1}{7}\cdot\dfrac{5}{9}+\dfrac{5}{9}\cdot\dfrac{2}{7}+\dfrac{5}{9}\cdot\dfrac{1}{7}+\dfrac{5}{9}\cdot\dfrac{3}{7}\)
=5/9(1/7+2/7+1/7+3/7)
=5/9*1
=5/9
\(\frac{1}{3}\cdot y+2=\frac{1}{5}\cdot y+\frac{7}{2}\)
\(=>\frac{1}{3}\cdot y-\frac{1}{5}\cdot y=\frac{7}{2}-2\)
\(=>y\cdot\left(\frac{1}{3}-\frac{1}{5}\right)=\frac{3}{2}\)
\(=>y\cdot\frac{2}{15}=\frac{3}{2}\)
\(=>y=\frac{3}{2}:\frac{2}{15}=\frac{45}{4}\)
theo de bai ta co 1/3.y+2=1/5.y+7/2
=>y/3+2=y/5+7/2
=>y+6/3=2y+35/10
=>6y+105=10y+60
=>16y=165
=>y=165/16
=6/1=6
ht