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59 + 5 + 1 = ...
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\(\dfrac{5}{12}+\dfrac{1}{6}=\dfrac{5}{12}+\dfrac{2}{12}=\dfrac{5+2}{12}=\dfrac{7}{12}\)
\(\dfrac{5}{12}+\dfrac{1}{6}=\dfrac{5}{12}+\dfrac{2}{12}=\dfrac{7}{12}\)
\(1-\dfrac{23}{47}=\dfrac{47}{47}-\dfrac{23}{47}=\dfrac{24}{47}\)
\(\dfrac{4}{5}x\dfrac{7}{8}=\dfrac{4x7}{5x8}=\dfrac{28}{40}=\dfrac{7}{10}\)
\(\dfrac{8}{5}:\dfrac{1}{4}=\dfrac{8}{5}x\dfrac{4}{1}=\dfrac{32}{5}\)
5 - 1 - 1 = 3 4 - 1 - 1 = 2 3 - 1 - 1 = 1
5 - 1 - 2 = 2 5 - 2 - 1 = 2 5 - 2 - 2 = 1
Lời giải chi tiết:
5 – 2 – 1 = 2 | 4 – 2 – 1 = 1 | 3 – 1 – 1 = 1 |
5 – 2 – 2 = 1 | 5 – 1 – 2 = 2 | 5 – 1 – 1 = 3 |
a.
\(\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{12}\right)+\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{5}{4}+\frac{3}{5}+\frac{3}{8}-\frac{7}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{12}{11}\right)\)
\(=\frac{-9}{10}\)
b.
\(\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{15}\right)+\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{3}{8}-\frac{7}{5}+\frac{5}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{15}{11}\right)\)
\(=\frac{-9}{8}\)
59 + 5 + 1 = ( 59 + 1) + 5 = 60 + 5 = 65
Số cần điền vào chỗ trống là 65
= 65