Tính bằng cách thuận tiện nhất
13/19x(19/13-7/9)
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`4/6+7/13+17/9+19/13+1/9+14/6`
`=(4/6+14/6)+(7/13+19/13)+(17/9+1/9)`
`=18/6+26/13+18/9`
`=3+2+2`
`=7`
\(\frac{13}{19}\times\left(\frac{19}{13}-\frac{7}{9}\right)\\ =\frac{13}{19}\times\frac{19}{13}-\frac{13}{19}\times\frac{7}{9}\)
\(=1-\frac{91}{171}\)
\(=\frac{80}{171}\)
Thấy đúng thì k đúng giúp mik
\(\frac{4}{6}+\frac{7}{13}+\frac{17}{9}+\frac{19}{13}+\frac{1}{9}+\frac{14}{6}\)
\(=\left(\frac{4}{6}+\frac{14}{6}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)+\left(\frac{17}{9}+\frac{1}{9}\right)\)
\(=3+2+2=7\)
4/6 + 7/13 + 17/9 + 19/13 + 1/9 + 14/6. = ( 4/6 + 14/6 ) + ( 7/13 + 19/13 ) + ( 17/9 + 1/9 ). = 18/6 + 26/13 + 18/9. = 3 + 2 + 2 = 7.
a) 47,54+18,72+5,13-17,54-7,72+4,87=(47,54-17,54)+(18,72-7,72)+(4,87+5,13)=30+11+10=51
b)4/7+7/13+17/9+19/13-8/9+17/7=(4/7+17/7)+(7/13+19/13)+(17/9-8/9)=3+2+1=6
AI lấy đêf kiểm tra toán giữa kì 1 không
ai nhanh thì mình sẽ cho
\(=\dfrac{5}{9}\times\dfrac{7}{4}+\dfrac{13}{9}\times\dfrac{7}{4}\\ =\left(\dfrac{5}{9}+\dfrac{13}{9}\right)\times\dfrac{7}{4}\\ =2\times\dfrac{7}{4}\\ =\dfrac{7}{2}\)
13/19 x 23/11 - 13/19 x 8/11 - 13/19 x 4/11
= 13/19 x (23/11 - 8/11 - 4/11)
= 13/19 x 1
= 13/19
\(\dfrac{13}{19}\times\dfrac{23}{11}-\dfrac{13}{19}\times\dfrac{8}{11}-\dfrac{13}{19}\times\dfrac{4}{11}\\ =\dfrac{13}{19}\times\left(\dfrac{23}{11}-\dfrac{8}{11}-\dfrac{4}{11}\right)\\ =\dfrac{13}{19}\times1=\dfrac{13}{19}\)
A =\(\frac{2}{5}\times\frac{4}{7}+\frac{3}{5}\times\frac{4}{7}\) B = \(\frac{17}{13}\times\frac{12}{17}-\frac{4}{13}\times\frac{12}{17}\) C = \(\frac{9}{14}:\frac{6}{7}+\frac{5}{14}:\frac{6}{7}\) D =\(\frac{9}{12}:\frac{7}{9}\times\frac{12}{19}\)
= \(\frac{4}{7}\times\left(\frac{2}{5}+\frac{3}{5}\right)\) =\(\left(\frac{17}{13}-\frac{4}{13}\right)\times\frac{12}{17}\) = \((\frac{9}{14}+\frac{5}{14}):\frac{6}{7}\) = \(\frac{9}{12}\times\frac{9}{7}\times\frac{12}{19}\)
=\(\frac{4}{7}\times1\) = \(1\times\frac{12}{17}\) = \(1:\frac{6}{7}\) = \(\frac{9\times9\times12}{12\times7\times19}\)
=\(\frac{4}{7}\) = \(\frac{12}{17}\) =\(\frac{7}{6}\) = \(\frac{9\times9}{7\times19}=\frac{81}{133}\)
13/19x(19/13-7/9)
= 13/19x19/13-13/19
\(\frac{13}{19}×\left(\frac{13}{19}-\frac{7}{9}\right)\)
=\(\frac{13}{19}×-\frac{16}{171}\)
=\(-\frac{208}{3249}\)