Lưu ý / là phần * là nhân
Tìm y biết : 7/10 - y * = 1/5
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) Ta có: \(\frac{3+x}{5+y}=\frac{3}{5}\)
=> (3 + x).5 = 3(5 + y)
=> 15 + 5x = 15 + 3y
=> 5x = 3y
=> x = 3/5y
Mà x + y = 16
hay 3/5y + y = 16
=> (3/5 + 1).y = 16
=> 8/5.y = 16
=> y = 16 : 8/5
=> y = 10
=> x = 16 - 10 = 6
Vậy x = 6; y = 10
b) Ta có: \(\frac{x-7}{y-6}=\frac{7}{6}\)
=> (x - 7).6 = 7.(y - 6)
=> 6x - 42 = 7y - 42
=> 6x = 7y
=> x = 7/6y
Mà x - y = -4
hay 7/6y - y = -4
=> 1/6y = -4
=> y = -4 : 1/6
=> y = -24
=> x = -4 - 24 = -28
Vậy x = -28; y = -24
\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{8}=\frac{y}{12}\)
\(\frac{y}{z}=\frac{4}{5}\Rightarrow\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{y}{12}=\frac{z}{15}\)
nên :
\(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)
\(\Rightarrow\frac{x+y-z}{8+12-15}=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\) mà x + y - z = 10
\(\Rightarrow\frac{10}{5}=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)
\(\Rightarrow2=\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)
\(\Rightarrow\hept{\begin{cases}x=2\cdot8=16\\y=2\cdot12=24\\z=2\cdot15=30\end{cases}}\)
vậy_
?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????//
a) \(\frac{x}{6}=\frac{5}{24}\Rightarrow x=\frac{5}{24}.6=\frac{5}{4}\)
b) \(-\frac{4}{y}=\frac{20}{14}\Rightarrow y=-4:\frac{20}{14}=-\frac{14}{5}\)
c) \(\frac{4}{7}=\frac{12}{x}\Rightarrow x=12:\frac{4}{7}=21\)
d) \(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3}{7}.21=9\)
a)-6x=6
x=-1
b)8x=35->x=35/8
c)8|x|=35->|x|=35/2->x=35/2;x=-35/2
mấy ý kia tương tự bạn ạ!
Bài làm:
\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).y=\frac{2}{3}\)
\(\Leftrightarrow\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).y=\frac{4}{3}\)
\(\Leftrightarrow\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+\frac{9-7}{7.9}+\frac{11-9}{9.11}\right).y=\frac{4}{3}\)
\(\Leftrightarrow\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).y=\frac{4}{3}\)
\(\Leftrightarrow\left(1-\frac{1}{11}\right).y=\frac{4}{3}\)
\(\Leftrightarrow\frac{10}{11}.y=\frac{4}{3}\)
\(\Leftrightarrow y=\frac{4}{3}:\frac{10}{11}=\frac{4}{3}.\frac{11}{10}=\frac{22}{15}\)
Chú ý dấu \(\left(.\right)\)là dấu \(\left(\times\right)\)
Vậy \(y=\frac{22}{15}\)
\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right).y=\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{2}.\left(1-\frac{1}{11}\right).y=\frac{2}{3}\)
\(\Leftrightarrow\frac{1}{2}.\frac{10}{11}.y=\frac{2}{3}\)
\(\Leftrightarrow\frac{5}{11}.y=\frac{2}{3}\)
\(\Rightarrow y=\frac{2}{3}:\frac{5}{11}=\frac{22}{15}\)
LƯU Ý:các dấu chấm(.) là dấu nhân ^^.
y = (7/10 - 1/5) : 2
y = (7/10 - 2/10) : 2
y = 5/10 : 2
y = 1/2 : 2
y = 1/4
Bạn sai rồi