Question

[Linh Bùi]

Bài 1: Tính

a) \(\frac{30x^3}{11y^2}.\frac{121y^5}{25x}\)

b) \(\frac{24y^5}{7x^2}.\frac{-21x}{12y^3}\)

c) \(\left(\frac{-18y^3}{25x^4}\right).\left(\frac{-15x^2}{9y^3}\right)\)

d) \(\frac{3x^2}{2y}.\frac{1}{4y}.\frac{5}{3y}\)

e) \(\frac{2x}{3}.\frac{x+1}{2x}\)

g) \(\frac{5-x}{x-3}.\frac{2}{3}.\frac{x}{4}\)

( giúp mink vs mink đag cần gấp)

Answer 1

[Bùi Thị Phương Anh]

\(a,\frac{30x^3}{11y^2}.\frac{121y^5}{25x}\)

\(=>\frac{30x^3.121y^5}{11y^2.25x}=\frac{6x^2.11y^3}{5}=\frac{66x^2.y^3}{5}\)

\(b,\frac{24y^5}{7x^2}.\frac{-21x}{12y^3}\)

\(=>\frac{24y^5.\left(-21\right)x}{7x^2.12y^3}=\frac{2y^2.\left(-3\right)}{x}=-\frac{6y^2}{x}\)

\(c,\left(\frac{-18y^3}{25x^4}\right).\left(\frac{-15x^2}{9y^3}\right)\)

\(=>\frac{-18y^3.\left(-15\right)x^2}{25x^4.9y^3}=\frac{-2.\left(-3\right)}{5x^2}=\frac{6}{5x^2}\)

\(d,\frac{3x^2}{2y}.\frac{1}{4y}.\frac{5}{3y}\)

\(=>\frac{3x^2.1.5}{2y.4y.3y}=\frac{15x^2}{24y^3}=\frac{5x^2}{8y^3}\)

\(e,\frac{2x}{3}.\frac{x+1}{2x}\)

\(=>\frac{2x\left(x+1\right)}{3.2x}=\frac{x+1}{3}\)

\(g,\frac{5-x}{x-3}.\frac{2}{3}.\frac{x}{4}\)

\(=>\frac{2x\left(5-x\right)}{3.4\left(x-3\right)}=\frac{10x-2x^2}{12\left(x-3\right)}=\frac{10x-2x^2}{12x-9}\)