Tính cách thuận tiện nhất : \(\frac{7}{19}\times\frac{1}{3}+\frac{7}{19}\times\frac{2}{3}\)
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a) \(\left(\frac{3}{5}.\frac{5}{3}\right).\frac{8}{27}\)
= \(1.\frac{8}{27}\)
=\(\frac{8}{27}\)
b) \(\frac{7}{19}.\left(\frac{1}{3}.\frac{2}{3}\right)\)
= \(\frac{7}{19}.\frac{2}{9}\)
=\(\frac{14}{81}\)
Không biết có đúng không? Tick mình nha !
\(\frac{3}{5}.\frac{8}{27}.\frac{5}{3}=1.\frac{8}{27}.1=\frac{8}{27}\)
\(\frac{7}{19}.\frac{1}{3}+\frac{7}{19}.\frac{2}{3}=\frac{7}{19}.\left(\frac{1}{3}+\frac{2}{3}\right)=\frac{7}{19}.1=\frac{7}{19}\)
\(\frac{12}{5}.4-4.\frac{7}{5}=4\left(\frac{12}{5}-\frac{7}{5}\right)=4.1=4\)
\(\frac{3}{5}x\frac{8}{27}x\frac{5}{3}\)
\(=\frac{3}{5}x\frac{5}{3}x\frac{8}{27}\)
\(=1x\frac{8}{27}\)
\(=\frac{8}{27}\)
\(\frac{7}{19}x\frac{1}{3}+\frac{7}{19}x\frac{2}{3}\)
\(=\frac{7}{19}x\left(\frac{1}{3}+\frac{2}{3}\right)\)
\(=\frac{7}{19}x1=\frac{7}{19}\)
\(\frac{12}{5}x4-4x\frac{7}{5}\)
\(=4x\left(\frac{12}{5}-\frac{7}{5}\right)\)
\(=4x1=4\)
Đúng luôn nên các bn nhớ k mk nhé
\(=\frac{2}{3}\)x \(\left(\frac{5}{12}+\frac{7}{12}\right)\)+\(\frac{1}{3}\)
\(=\frac{2}{3}\)x \(1\)+\(\frac{1}{3}\)= \(\frac{2}{3}+\frac{1}{3}\)= \(\frac{3}{3}=1\)
= 2/3 x ( 5/12+7/12 ) +1/3
= 2/3 X 1 +1/3
= 2/3+ 1/3 = 1
a) = -3/7 . 5/11 + -3/7 . 6/11 + 9/7
= -3/7. ( 5/11 + 6/11 ) + 9/7
= -3/7. 1 + 9/7
= -3/7 + 9/7
= 6/7
b) = 4/13 + 9/13 + -11/5 + 6/5 - 3/4
= 13/13 + -5/5 - 3/4
= 1 + (-1) - 3/4
= 0 - 3/4
= -3/4
c) = -19/17. 4/7 + 19/17. -3/7 + 19/17
= 19/17. -4/7 + 19/17. -3/7 + 19/17.1
= 19/17.( -4/7 + -3/7 + 19/17
= 19/17. -7/7 + 19/17
= 19/17. (-1) + 19/17
= -19/17 + 19/17
= 0
tk mk nha,thanks
a) \(\frac{3}{5}\times\frac{8}{27}\times\frac{5}{3}\)
\(=\left(\frac{3}{5}\times\frac{5}{3}\right)\times\frac{8}{27}\)
\(=1\times\frac{8}{27}\)
\(=\frac{8}{27}\)
b) \(\frac{7}{19}\times\frac{1}{3}+\frac{7}{19}\times\frac{2}{3}\)
\(=\frac{7}{19}\times\left(\frac{1}{3}+\frac{2}{3}\right)\)
\(=\frac{7}{19}\times1\)
\(=\frac{7}{19}\)
\(\frac{7}{19}\)x\(\frac{1}{3}\)+\(\frac{7}{19}\)x\(\frac{2}{3}\)=\(\frac{7}{19}\)x(\(\frac{1}{3}\)+\(\frac{2}{3}\))=\(\frac{7}{19}\)x1=\(\frac{7}{19}\)
\(\frac{7}{19}\)x \(\frac{1}{3}\)x \(\frac{7}{19}\)x \(\frac{2}{3}\)
= \(\frac{7}{19}\)x (\(\frac{1}{3}\)+ \(\frac{2}{3}\))
= \(\frac{7}{19}\)x 1
= \(\frac{7}{19}\)
Chúc bạn học tốt!