Tìm x biết
‐2/7÷15/14=‐21/20÷(5×x)
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Bài 1:
a) \(\frac{16}{15}.\frac{\left(-5\right)}{14}.\frac{54}{24}.\frac{56}{21}\)
\(=\frac{4.2.2}{5.3}.\frac{\left(-5\right)}{2.7}.\frac{3.3}{4}.\frac{8}{3}\)
\(=\frac{4.2.2.\left(-5\right).3.3.8}{5.3.2.7.4.3}\)
\(=\frac{-16}{7}\)
b) \(\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{15}{21}.\frac{4}{\left(-5\right)}\)
\(=\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{5}{7}.\frac{2.2}{\left(-5\right)}\)
\(=\frac{7.\left(-5\right).5.2.2}{3.2.7.\left(-5\right)}\)
\(=\frac{10}{3}\)
Bài 2:
a) \(\frac{21}{24}.\frac{11}{9}.\frac{5}{7}=\frac{7}{8}.\frac{11}{9}.\frac{5}{7}=\frac{11.5}{8.9}=\frac{55}{72}\)
b) \(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}\)
\(=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)
c) \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}\)
\(=1-1\frac{14}{15}=\frac{14}{15}\)
Bài 3:
a) x/5 = 2/5
=> x =2
b) -4/x = 20/14 = 10/7
=> -4/x = 10/7
=> x.10 = (-4).7
x.10 = - 28
x= -28 :10
x= -2,8
c) 4/7 = 12/x = 12/ 21
=> 12/x = 12/21
=> x = 21
d) 3/7 = x / 21 = 9/21
=> x/21 = 9/21
=> x= 9
tính trừ bt nha bạn vế thương thì cũng tĩnh ra xong mới tính nha
a) đề kiểu gì vậy bạn
b) \(x+\frac{2}{14}=\frac{3}{21}\Leftrightarrow x=0\)
c) \(x+\frac{2}{7}=\frac{1}{2}\Leftrightarrow x=\frac{3}{14}\)
d) \(\frac{12}{15}=\frac{x-5}{10}\Leftrightarrow15x-75=120\Leftrightarrow15x=195\Leftrightarrow x=13\)
1. -x+20 = -(-15)-8+13
=> -x=15-8+13-20
=> -x=0
=> x=0
2. -(-10)+x=-13+(-9)+(-6)
=> 10+x=-13-9-6
=> x = -13-9-6-10
=> x = -38
3. 8-(-12)+10=-(-14)-x
=> 8+12+10=14-x
=> x = 14-8-12-10
=> x = -16
4. -(+12)+(-x)-(-3)=5-(-7)
=> -12-x+3=5+7
=> -x=5+7+12-3
=> -x=21
=> x=-21
5. 14-x+(-10)=-(-9)+(+15)
=> 14-x-10=9+15
=> -x=9+15-14+10
=> -x=20
=> x=-20
6. 12-(-17)+(-3)=-5+x
=> 12+17-3+5=x
=> x=31
7. x-(-19)-(+32)=14-(+16)
=> x+19-32=14-16
=> x=14-16+32-19
=> x=11
8. x-|-15|-|7|=-(-9)+|-5|
=> x-15-7=9+5
=> x=9+5+7+15
=> x=36
9. 15-x+17=13-(-21)
=> 15-x+17=13+21
=> -x=13+21-15-17
=> -x=2
=> x=-2
10. -|-5|-(-x)+4=3-(-25)
=> -5+x+4=3+25
=> x=3+25-4+5
=> x=29
tìm x,biết
5-x-16=40+x
4x-10=15-x
15-x=4x-5
x-15=6+4x
-12+x=5x-20
7x-4=20+3x
5x-7=-21-2x
x+15=20-4x
17-x=7-6x
d) |2x – 5| –7 = 22
| 2x -5 | = 22+7
| 2x -5 | = 29
TH1: 2x-5 = -29
2x = -29+5
2x= -24
x= -24:2
x= -12
TH2: 2x -5 =29
2x = 29+5
2x= 34
x= 34:2
x= 17
Vậy...
\(\frac{-2}{7}\div\frac{15}{14}=\frac{-21}{20}\div\left(5\times x\right)\)
\(\Rightarrow\frac{-4}{15}=\frac{-21}{20}\div\left(5\times x\right)\)
\(\Rightarrow5\times x=\frac{-21}{20}\div\frac{-4}{15}\)
\(\Rightarrow5\times x=\frac{63}{16}\)
\(\Rightarrow x=\frac{63}{16}\div5\)
\(\Rightarrow x=\frac{63}{80}\)
~ học tốt nha ~
\(\frac{-2}{7}:\frac{15}{14}=\frac{-21}{20}:(5\cdot x)\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{7}:\frac{15}{14}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{7}\cdot\frac{14}{15}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{-2}{1}\cdot\frac{2}{15}\)
\(\Leftrightarrow\frac{-21}{20}:(5\cdot x)=\frac{4}{15}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{20}:\frac{4}{15}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{20}\cdot\frac{15}{4}\)
\(\Leftrightarrow5\cdot x=\frac{-21}{4}\cdot\frac{3}{4}\)
\(\Leftrightarrow5\cdot x=\frac{-63}{16}\)
\(\Leftrightarrow x=\frac{-63}{16}:5\)
\(\Leftrightarrow x=\frac{-63}{16}\cdot\frac{1}{5}=\frac{-63}{80}\)