Cho A= 16^10/8^12. Hãy viết a dưới dạng 1 lũy thừa
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\(4=2^2\)
\(8=2^3\)
\(9=3^2\)
\(16=4^2\)
\(64=2^6\)
\(100=10^2\)
\(25=5^2\)
\(144=12^2\)
a) 8 = 23
425 = 25.35.75
16 = 24
b) (0,09)3 = (3/10)6
(3/10)8 = (3/10)8
0,027 = (3/10)3
`@` `\text {Ans}`
`\downarrow`
`a)`
`8 = 2^3`
`32^5` chứ ạ?
`32^5 = (2^5)^5 = 2^10`
`16 = 2^4`
`b)`
`(0,09)^3 = (0,3^2)^3 = 0,3^6` hay `(3/10)^6`
`(3/10)^8 = (3/10)^8`
`(0,027) = (0,3)^3` hay `(3/10)^3`
`@` `\text {Kaizuu lv uuu}`
1.
a) \(3^4\times3^5\times3^6=3^{4+5+6}=3^{15}\)
b) \(5^2\times5^4\times5^5\times25=5^2\times5^4\times5^5\times5^2=5^{2+4+5+2}=5^{13}\)
c) \(10^8\div10^3=10^{8-3}=10^5\)
d) \(a^7\div a^2=a^{7-2}=a^5\)
2.
\(987=900+80+7\\ =9\times100+8\times10+7\\ =9\times10^2+8\times10^1+7\times10^0\)
\(2021=2000+20+1\\ =2\times1000+2\times10+1\times1\\ =2\times10^3+2\times10^1+1\times10^0\)
\(abcde=a\times10000+b\times1000+c\times100+d\times10+e\times1\\ =a\times10^4+b\times10^3+c\times10^2+d\times10^1+e\times10^0\)
a) 7.7.8.8 = 72.82 = (7.8)2 = 562
b) 9.10.12.16 = 32.2.5.22.3.24 = 33.26.5 = (3.22)3.5 = 123.5
c) 493:74 = (72)3:74 = 76 : 74 = 72
-8.(-2)5.(-23. \(\dfrac{1}{16}\)) = 256 . \(\dfrac{-1}{2}\) = -128 = (-2)7
\(A=\frac{16^{10}}{8^{12}}=\frac{\left(2^4\right)^{10}}{\left(2^3\right)^{12}}=\frac{2^{40}}{2^{36}}=2^4\)
A = 1610 / 812
=> A = ( 24)10 / ( 23)12
=> A = 240 / 236
=> A = 24