7/12 - 0,75 : (4x-3)^2 = -3/2
giúp mk vói ai nhanh mk tặng 3 tk
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( 5/4x - 2/3 )^4 = 57/16 + 3/2
=> ( 5/4x - 2/3 )^4 = 81/16
=> ( 5/4x - 2/3 )^4 = 3^4/2^4
=> 5/4x - 2/3 = 3/2
=> 5/3x = 13/6
=> x = 13/10
Vậy x = 13/10
\(\left(\frac{5}{4}x-\frac{2}{3}\right)^4-\frac{3}{2}=\frac{57}{16}\)
\(\left(\frac{5}{4}x-\frac{2}{3}\right)^4-\frac{3}{2}=\frac{57}{16}+\frac{3}{2}\)
\(\left(\frac{5}{4}x-\frac{2}{3}\right)=\frac{81}{16}\)
Ta xét 2th:
Th1: \(\frac{5}{4}x-\frac{2}{3}=\left(\frac{81}{16}\right)^{\frac{1}{4}}\)
\(\Rightarrow x=\frac{26}{15}\)
Th2: \(\frac{5}{4}x-\frac{2}{3}=-\left(\frac{81}{16}\right)^{\frac{1}{4}}\)
\(\Rightarrow x=-\frac{2}{3}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{26}{15}\\x=-\frac{2}{3}\end{cases}}\)
để G lớn nhất thì :
\(|4x-1|\);\(|xy-3|\)nhỏ nhất và bằng 0
=> 4x-1 =0 1/4 . y-3=0
x= (1+0) :4 y=(0+3) :1/4
x=1/4 =>x=1/4 y=12
=> G= 3 - \(|4x-1|\)- \(|xy-3|\)
=> G=3-0-0=3
vậy maxG=3
B= 0,5 .4/3 .(-10) .0,75 .7/-35
B= 1/2 .4/3 .(-10) .3/4 .(-1)/5
B= [1/2 .(-1)/5 .(-10) ] .(4/3 .3/4)
B= 1 .1
B= 1
Mình làm luôn nhé !!!
= ( x + 16 ) x 12 = 240 - 180
= ( x + 16 ) x 12 = 60
= ( x + 16 ) = 60 : 12
= ( x + 16 ) = 5
= x = 5 - 16
= x = - 11
240 - (x + 16) : x . 12 = 180
(x + 16) : x . 12 = 240 - 180
(x + 16) : x . 12 = 60
(x + 16) : x = 60 : 12
(x + 16) : x = 5
x + 16 = 5
x = 5 - 16
x = -11
(2,5x - 4/3)2 - 5/6 = -7/18
=> (2,5x - 4/3)2 = -7/18 + 5/6
=> (2,5x - 4/3)2 = 4/9
=> (2,5x - 4/3)2 = (2/3)2
=> \(\orbr{\begin{cases}2,5x-\frac{4}{3}=\frac{2}{3}\\2,5x-\frac{4}{3}=-\frac{2}{3}\end{cases}}\)
=> \(\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)
\(\left(2,5x-\frac{4}{3}\right)^2-\frac{5}{6}=-\frac{7}{18}\)
\(\left(2,5x-\frac{4}{3}\right)^2=-\frac{7}{18}+\frac{5}{6}\)
\(\left(2,5x-\frac{4}{3}\right)^2=\frac{4}{9}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{4}{15}\end{cases}}\)
5/6 - 7/4 .|-2x - 3/2| = 7/12
7/4 .|-2x - 3/2| = 5/6 - 7/12
7/4.|-2x - 3/2| = 1/4
|-2x- 3/2| = 1/4 : 7/4
|-2x - 3/2| = 1/7
\(\Rightarrow\orbr{\begin{cases}-2x-\frac{3}{2}=\frac{1}{7}\\-2x-\frac{3}{2}=-\frac{1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}-2x=\frac{23}{14}\\-2x=\frac{19}{14}\end{cases}}\Rightarrow\orbr{\begin{cases}x=-\frac{23}{28}\\x=-\frac{19}{28}\end{cases}}\)
a)\(\left(\frac{3}{4}+\frac{-7}{2}\right).\left(\frac{10}{11}+\frac{2}{22}\right)\)
\(\left(\frac{3}{4}+\frac{-14}{4}\right).\left(\frac{20}{22}+\frac{2}{22}\right)\)
\(\frac{-11}{4}.1=\frac{-11}{4}\)
câu b mk hiểu đề
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=\frac{-3}{2}\)
\(\frac{3}{4}:\left(4x-3\right)^2=\frac{25}{12}\)
\(\left(4x-3\right)^2=\frac{9}{25}=\left(\frac{\pm3}{5}\right)^2\)
+) 4x - 3 = 3/5
4x = 18/5
x = 9/10
+) 4x - 3 = -3/5
4x = 12/5
x = 3/5
Vậy,.........
\(\frac{7}{12}-0,75:\left(4x-3\right)^2=-\frac{3}{2}\)
\(\Leftrightarrow\frac{7}{12}.12\left(4x-3\right)^2-\frac{0,75}{\left(4x-3\right)^2}.12\left(4x-3\right)^2=-\frac{3}{2}.12\left(4x-3\right)^2\)
\(\Leftrightarrow7\left(4x-3\right)^2-9=-18\left(4x-3\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{9}{10}\\x=\frac{3}{5}\end{cases}}\)