So sánh 2 biểu thức :
A = 123 x 123
B = 121 x 124
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\(\dfrac{x+1}{124}+1+\dfrac{x+2}{123}+1=\dfrac{x+3}{122}+1+\dfrac{x+4}{121}+1\)
\(\Leftrightarrow\dfrac{x+125}{124}+\dfrac{x+125}{123}=\dfrac{x+125}{122}+\dfrac{x+125}{121}\)
\(\Leftrightarrow\left(x+125\right)\left(\dfrac{1}{124}+\dfrac{1}{123}-\dfrac{1}{122}-\dfrac{1}{121}\ne0\right)=0\Leftrightarrow x=-125\)
<=>\(\dfrac{x+1}{124}+\dfrac{x+2}{123}-\dfrac{x+3}{122}-\dfrac{x+4}{121}=0\)
<=>\(\left(\dfrac{x+1}{124}+1\right)+\left(\dfrac{x+2}{123}+1\right)-\left(\dfrac{x+3}{122}+1\right)-\left(\dfrac{x+4}{121}+1\right)=0\)
<=>\(\dfrac{x+125}{124}+\dfrac{x+125}{123}-\dfrac{x+125}{122}-\dfrac{x+125}{121}=0\)
<=>\(\left(x+125\right)\left(\dfrac{1}{124}+\dfrac{1}{123}-\dfrac{1}{122}-\dfrac{1}{121}\right)=0\)
<=>x+125=0
<=>x=-125
a) B = 124 x 122 = (123+1) x (123-1) = 123 x 123 -123 + 123 -1 = A -1
=> B < A
b) B = 986 x 985 = (987-1) x (984+1) = 987 x 984 + 987 - 984 -1 = A +2
=> B > A
a) Ta có: A = 123 x 123 = 123 x ( 124 - 1 ) = 123 x 124 - 123
B = 121 x 124 = ( 123 - 2 ) x 124 = 123 x 124 - 248
Suy ra: 123 x 124 - 123 > 123 x 124 - 248 hay A > B
b) Ta có: C = 123 x 137137 = 123 x 137 x 1001 = 137 x 123 x 1001
D = 137 x 123123 = 137 x 123 x 1001
Suy ra: C = D
c) Ta có: E = 2015 x 2017 = 2015 x ( 2016 + 1 ) = 2015 x 2016 + 2015
F = 2016 x 2016 = ( 2015 + 1 ) x 2016 = 2015 x 2016 + 2016
Suy ra: 2015 x 2016 + 2015 < 2015 x 2016 + 2016 hay E < F
A = 1 − 1 2 . 1 − 1 3 . 1 − 1 4 ... 1 − 1 19 . 1 − 1 20 A = 1 2 . 2 3 . 3 4 .... 18 19 . 19 20 A = 1 20 > 1 21
Vậy A> 1 21
Ta có :
\(121.124=\left(123-2\right)\left(123+2\right)=123^2-2^2< 123^2\)
\(\Rightarrow A< B\)
Đoan cuối là A>B nhs