\(B=\frac{1}{2}\)+\(\frac{-1}{5}\)+\(\frac{-5}{7}\)+\(\frac{1}{6}\)+\(\frac{-3}{35}\)+\(\frac{1}{3}\)+\(\frac{1}{41}\)E=40+\(\frac{3}{8^{ }}\)+\(\frac{7}{8^2}\)+\(\frac{5}{8^3}\)+\(\frac{32}{8^5}\)F=\(\frac{147}{7^3}\)+4+\(\frac{35}{7^7}\)+\(\frac{4}{7^2}\)+\(\frac{27}{7^5}\)+\(\frac{-9}{7}\)đây là toán lớp 6 lên các bạn đừng thắc...
Đọc tiếp
\(B=\frac{1}{2}\)+\(\frac{-1}{5}\)+\(\frac{-5}{7}\)+\(\frac{1}{6}\)+\(\frac{-3}{35}\)+\(\frac{1}{3}\)+\(\frac{1}{41}\)
E=40+\(\frac{3}{8^{ }}\)+\(\frac{7}{8^2}\)+\(\frac{5}{8^3}\)+\(\frac{32}{8^5}\)
F=\(\frac{147}{7^3}\)+4+\(\frac{35}{7^7}\)+\(\frac{4}{7^2}\)+\(\frac{27}{7^5}\)+\(\frac{-9}{7}\)
đây là toán lớp 6 lên các bạn đừng thắc mắc
a: \(B=\left(-\dfrac{1}{5}-\dfrac{5}{7}+\dfrac{-3}{35}\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{2}\right)+\dfrac{1}{41}\)
\(=\dfrac{-7-25-3}{35}+\dfrac{3+2+1}{6}+\dfrac{1}{41}=\dfrac{42}{41}-1=\dfrac{1}{41}\)