\(5^{-2}.5^x+25.5^x=626.5^5\) tìm x
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\(25\).\(5^x\) = \(5^5\)
\(5^2\) . \(5^x\) = \(5^5\)
\(5^x\) = \(5^5\) : \(5^2\)
\(5^x\) = \(5^3\)
vậy x = 3
2x . 26 . 24 = 23 . 260
2x + 6 + 4 = 23 + 60
2x + 10 = 263
=> x + 10 = 63
x = 63 - 10
x = 53
a/ 5x.52.53=52.540
5x.55=542
5x=537
x=37
b/ 2x.26.24=23.260
2x.210=263
2x=253
x=53
525.5x-1=525
5x-1=525:525
5x-1= 50
=>x-1=0
x=0+1
x=1
vậy x=1
a) \(x-1\frac{4}{5}=\frac{10}{5}\)
\(\Rightarrow x=2+1\frac{4}{5}=3\frac{4}{5}=\frac{19}{5}\)
b) \(5,85:x=26-25,5\)
\(\Leftrightarrow5,85:x=0,5\)
\(\Rightarrow x=5,85:0,5=11,7\)
c) \(151-\left(-2\right).\left(x-6\right)=2227:17=131\)
\(\Rightarrow\left(-2\right).\left(x-6\right)=151-131=20\)
\(\Rightarrow\left(x-6\right)=20:\left(-2\right)=-10\)
\(\Rightarrow x=-4\)
d) \(\frac{2}{3}-\frac{1}{3}x=\frac{1}{4}\)
\(\Rightarrow \frac{1}{3}x=\frac{2}{3}-\frac{1}{4}=\frac{5}{12}\)
\(\Rightarrow x=\frac{5}{12}:\frac{1}{3}=\frac{5}{4}\)
dấu chấm (.) là dấu nhân nhé
52. 5X+ 2= 53. 53
52. 5X+ 2= 56
5X+ 2= 56: 52
5X+2= 54
=> X+ 2= 4
X= 4- 2
X=2
\(20\%\times25,5+\dfrac{1}{5}\times15,5+0,2\times59\)
\(=\dfrac{1}{5}\times25,5+\dfrac{1}{5}\times15,5+\dfrac{1}{5}\times59\)
\(=\dfrac{1}{5}\times\left(25,5+15,5+59\right)\)
\(=\dfrac{1}{5}\times100\)
\(=20\)
Giải:
a) \(25.5^{x+5}=5^8\)
\(\Leftrightarrow5^2.5^{x+5}=5^8\)
\(\Leftrightarrow5^{x+7}=5^8\)
\(\Leftrightarrow x+7=8\)
\(\Leftrightarrow x=1\)
Vậy ...
b) \(124+\dfrac{225}{\left(x-3\right)^2}=57\)
\(\Leftrightarrow\dfrac{15^2}{\left(x-3\right)^2}=-67\)
\(\Leftrightarrow\left(\dfrac{15}{x-3}\right)^2=-67\)
Mà \(\left(\dfrac{15}{x-3}\right)^2\ge0,\forall x\left(x\ne3\right)\)
Suy ra không có x thỏa mãn
Vậy ...
\(\Leftrightarrow5^x\left(5^{-2}.5^2\right)=5^4.5^5\)
\(\Leftrightarrow5^x.1=5^9\Rightarrow5^x=5^9=1953125\)