miếng bìa hình bình hành có độ dài đáy là 28cm, chiều cao bằng 4/7 độ dài đáy. Tính diện tích miếng bìa ?
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a) Hiệu số phần bằng nhau là:
5 - 3 = 2 (phần)
Độ dài đáy là:
28 : 2 x 5 = 70 (cm)
Chiều cao là:
28 : 2 x 3 = 42 (cm)
Đ/S: độ dài đáy: 70 cm
chiều cao: 42 cm
b) Diện tích HBH là:
70 x 42 = 2940 (cm2)
Đ/S: 2940 cm2
Ta có sơ đồ:
Đáy /........../........../........../........../........../
Chiều cao/........../........../........../ 28 cm
a)Chiều cao của miếng bìa là:
28 : (5 - 3) x 3 = 42 (cm)
Độ dài đáy của miếng bìa là:
42 + 28 = 70 (cm)
b) Diện tích miếng bìa là:
42 x 70 = 2940 (cm2)
Chiều cao là :
32 x 3: 4 = 24 ( m )
Diện tích hình bình hành là :
24 x 32 = 768 ( m2 )
a) Độ dài đáy hình bình hành là:
28 : 2 x 5 = 70 ( cm )
Chiều cao hình bình hành là:
70 - 28 = 42 ( cm )
b) Diện tích miếng bìa hình bình hành là:
70 x 42 = 2940 ( cm\(^2\))
Đáp số: 2940 cm\(^2\)
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Chiều cao miếng bìa là :
28 × 4/7 = 16 ( cm )
Diện tích miếng bìa là :
28 × 16 = 448 ( cm2 )
Đáp số : 448 cm2
CHÚC BẠN HỌC GIỎI !!!
Chiều cao là:
28 : 7 x 4 = 16 (cm)
Diện tích miếng bìa là:
16 x 28 = 448 (cm2)
Đáp số : 448 cm2
Tk mk nha!