- M=(\(\frac{3}{5}\)+0,415)+\(\frac{1}{200}\):0,01
N=30,75+\(\frac{1}{12}\)+3\(\frac{1}{6}\)
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Những câu hỏi liên quan
10 tháng 5 2016
\(\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}=\frac{\left(\frac{121}{200}+\frac{83}{200}\right):\frac{1}{100}}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}=\frac{\frac{51}{50}.100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
=\(\frac{102}{-34}=-3\)
28 tháng 4 2016
Ta có : \(B=\frac{\left(\frac{11^2}{200}+0,415\right):0,01}{\frac{1}{12}-37,25+3\frac{1}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{415}{1000}\right):\frac{1}{100}}{\frac{1}{12}-\frac{3725}{100}+\frac{19}{6}}\)
\(=>B=\frac{\left(\frac{121}{200}+\frac{83}{200}\right)\cdot100}{\frac{1}{12}-\frac{149}{4}+\frac{19}{6}}\)
\(=>B=\frac{\frac{204}{200}\cdot100}{\frac{1}{12}-\frac{447}{12}+\frac{38}{12}}\)
\(=>B=\frac{\frac{204\cdot100}{200}}{-\frac{408}{12}}=\frac{\frac{204}{2}}{-34}=\frac{102}{-34}=-3\)
TN
0
17 tháng 5 2016
Câu 2 :
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{12}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{25}{100}\right).\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{28}{15}.\frac{3}{4}-\frac{47}{60}.\frac{24}{47}-\frac{51}{13}:3\)
\(\frac{7}{5}-\frac{2}{5}-\frac{51}{13}.\frac{1}{3}\)
\(\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(-\frac{4}{13}\)
12 tháng 5 2018
(1/12+3 1/6-30,75).x -8 = (3/5+0,415+1/200):0,01
(1/12+19/6-123/4).x-8=(3/5+83/200+1/200):1/100
-55/2.x-8=51/50:1/100
-55/2.x-8=102
-55/2.x=102+8=110
x=110:-55/2=-4
2 tháng 7 2023
a: =>4x-5=0 hoặc 5/4x-2=0
=>x=5/4 hoặc x=2:5/4=2*4/5=8/5
b: =>(1/12+19/6-30,75)*x-8=102
=>-55/2x=110
=>x=-4
TT
3 tháng 5 2017
\(\left(\dfrac{1}{2}+\dfrac{19}{6}-30,75\right).x-8=\left(\dfrac{3}{5}+0,415+\dfrac{1}{200}\right):0.01\)
\(\left(\dfrac{1}{2}+\dfrac{19}{6}-\dfrac{123}{4}\right).x-8=\left(\dfrac{3}{5}+\dfrac{83}{200}+\dfrac{1}{200}\right):\dfrac{1}{100}\)
\(\dfrac{-325}{12}.x-8=\dfrac{51}{50}:\dfrac{1}{100}\)
\(\dfrac{-325}{12}.x-8=102\)
\(\dfrac{-325}{12}.x=102+8\)
\(\dfrac{-325}{12}.x=110\)
\(x=110:\dfrac{-325}{12}\)
\(x=\dfrac{-264}{65}\)
\(M=\left(\frac{3}{5}+0,415\right)+\frac{1}{200}\div0,01\)
\(M=\left(\frac{3}{5}+\frac{83}{200}\right)+\frac{1}{200}\div\frac{1}{100}\)
\(M=\frac{203}{200}+\frac{1}{200}\div\frac{1}{100}\)
\(M=\frac{203}{200}+\frac{1}{2}\)
\(M=\frac{303}{200}\)
\(N=30,75+\frac{1}{12}+3\frac{1}{6}\)
\(N=\frac{123}{4}+\frac{1}{12}+\frac{19}{6}\)
\(N=\frac{185}{6}+\frac{19}{6}\)
\(N=34\)