1/TÍNH NHANHa/ \(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)2/so sánha/\(\frac{2009}{2010}va\frac{2010}{2011}\) b/\(\frac{1}{3^{400}}va\frac{1}{4^{300}}\) c/\(\frac{...

NH

Nguyễn Hoàng Gia Hân

9 tháng 5 2018 - olm

1/TÍNH NHANHa/ \(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)2/so sánha/\(\frac{2009}{2010}va\frac{2010}{2011}\) b/\(\frac{1}{3^{400}}va\frac{1}{4^{300}}\) c/\(\frac{200}{201}+\frac{201}{202}va\frac{200+201}{201+202}\) d/\(\frac{2008}{2008+2009}va\frac{2009}{2009+2010}\)3/TÌM X BIẾT\(\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{97.99}\right)-x=\frac{-100}{99}\)GIÚP MÌNH NHA MAI MÌNH NỘP...

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#Toán lớp 6

1

NC

Nguyễn Công Tỉnh

9 tháng 5 2018

a/\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)

=\(\frac{2^3.5^3.7^4}{2^2.5^2.7^4}\)

=2.5

=10

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BH

Bao Huynh

25 tháng 4 2016 - olm

Tính nhanh:a) \(\left(\frac{67}{111}+\frac{2}{33}-\frac{15}{117}\right).\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)\)

b)\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)

#Toán lớp 6

0

LT

Le Tran Hoai My

19 tháng 4 2015 - olm

1) Tính:\(A=\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+........+\frac{2}{97.99}\)\(B=\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\) \(C=\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+.......\frac{1}{97.99}\) \(D=\left(\frac{\frac{12}{1}-\frac{12}{5}-\frac{12}{487}}{\frac{4}{1}-\frac{4}{5}-\frac{4}{487}}\right):\left(\frac{\frac{5}{1}+\frac{5}{17}+\frac{5}{37}}{\frac{6}{1}+\frac{6}{17}+\frac{6}{37}}\right).\frac{505}{1818}\)2) So...

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#Toán lớp 6

2

D

doremon

19 tháng 4 2015

B = \(\frac{2^3.5.7.5^2.7^3}{\left(2.5.7^2\right)^2}=\frac{2^3.5^3.7^4}{2^2.5^2.7^4}=\frac{2.5.1}{1.1.1}=10\)

C = \(\frac{1}{2}\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{97.99}\right)\)\(=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{97}-\frac{1}{99}\right)\)\(=\frac{1}{2}\left(\frac{1}{3}-\frac{1}{99}\right)=\frac{1}{2}\left(\frac{33}{99}-\frac{1}{99}\right)=\frac{1}{2}.\frac{32}{99}=\frac{16}{99}\)

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D

doremon

19 tháng 4 2015

1) \(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+....+\frac{2}{97.99}=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{97}-\frac{1}{99}=\frac{1}{3}-\frac{1}{99}=\frac{33}{99}-\frac{1}{99}=\frac{32}{99}\)

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QQ

Quan quan

23 tháng 4 2015 - olm

\(\left(\frac{1}{2011}+\frac{2}{2010}+\frac{3}{2009}+4\right):\left(\frac{1}{2009}+\frac{1}{2010}+\frac{1}{2011}+\frac{1}{2012}\right)\) = ?

#Toán lớp 6

0

NV

nguyễn văn hữu

1 tháng 2 2015 - olm

Tính: \(\left(-2\right)\left(\frac{-3}{2}\right)\left(\frac{-4}{3}\right)...\left(\frac{-2010}{2009}\right)\left(\frac{-2011}{2010}\right)\)

#Toán lớp 7

0

LP

Le Phuc Thuan

21 tháng 2 2017 - olm

\(\frac{x_1-1}{2010}=\frac{x_2-2}{2009}=.....=\frac{x_{2010}-2010}{1}\)va \(x_1+x_2+x_3+...+x_{2011}=2\left(1+2+3+...+2011\right)\)

#Toán lớp 7

0

‍

15 tháng 10 2020 - olm

a, Tính : \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)b, Tính : \(P=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2012}}{\frac{2011}{1}+\frac{2010}{2}+\frac{2009}{3}+...+\frac{1}{2011}}\)c, Tính...

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#Toán lớp 7

0

AM

Aikatsu mizuki

12 tháng 7 2017 - olm

Bài 3 : a) Tính

\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)

b) Tính :

\(P=\frac{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2012}}{\frac{2011}{1}+\frac{2010}{2}+\frac{2009}{3}+\frac{1}{2011}}\)

#Toán lớp 6

0