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\(\frac{x}{1\cdot4}+\frac{x}{4\cdot7}+\frac{x}{7\cdot10}+\frac{x}{10\cdot13}+\frac{x}{13\cdot16}=\frac{5}{2}\)
\(\Rightarrow\frac{x}{3}\left[\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot10}+\frac{3}{10\cdot13}+\frac{3}{13\cdot16}\right]=\frac{5}{2}\)
\(\Rightarrow\frac{x}{3}\left[1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{16}\right]=\frac{5}{2}\)
\(\Rightarrow\frac{x}{3}\left[1-\frac{1}{16}\right]=\frac{5}{2}\)
\(\Rightarrow\frac{x}{3}\cdot\frac{15}{16}=\frac{5}{2}\)
\(\Rightarrow\frac{x}{3}=\frac{5}{2}:\frac{15}{16}\)
\(\Rightarrow\frac{x}{3}=\frac{5}{2}\cdot\frac{16}{15}\)
\(\Rightarrow\frac{x}{3}=\frac{1}{1}\cdot\frac{8}{3}\)
\(\Rightarrow\frac{x}{3}=\frac{8}{3}\Leftrightarrow x=8\)
a: =>x/16=3/8+7/2=3/8+28/8=31/8=62/16
=>x=62
b: =>3/5:x=17/10-2/5=17/10-4/10=13/10
=>x=3/5:13/10=3/5x10/13=30/65=6/13
1.
\(\left(x+\dfrac{1}{3}\right)^2=16\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{3}=4\\x+\dfrac{1}{3}=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=\dfrac{-13}{3}\end{matrix}\right.\)
2.
\(x+\dfrac{3}{10}=\dfrac{7}{5}\\ x=\dfrac{7}{5}-\dfrac{3}{10}\\ x=\dfrac{11}{10}\)
\(\left(x+\dfrac{1}{3}\right)^2=16\)
\(\left[{}\begin{matrix}\left(x+\dfrac{1}{3}\right)^2=4^2\\\left(x+\dfrac{1}{3}\right)^2=\left(-4\right)^2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x+\dfrac{1}{3}=4\\x+\dfrac{1}{3}=-4\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=4-\dfrac{1}{3}\\x=-4-\dfrac{1}{3}\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=\dfrac{-13}{3}\end{matrix}\right.\)
`5/[x-2]=10/16`
`10(x-2)=16.5=80`
`x-2=80:10=8`
`x=8+2=10`
\(\dfrac{5}{x-2}=\dfrac{10}{16}\)
\(\Rightarrow5.16=\left(x-2\right).10\)
\(\Rightarrow\left(x-2\right).10=80\)
\(\Rightarrow x-2=80:10\)
\(\Rightarrow x-2=8\)
\(\Rightarrow x=8+2\)
\(\Rightarrow x=10\)