`3^4 xx 2^2 - 3^6 xx 3^5 + 10 xx 3^4`

`= 3^4(2^2 - 3^3 + 10)`

`= 3^4 . 5`.

`= 81 xx 5`

`= 405`

Thấy: `2 xx 2048 = 4096 = 2^12 = 2^6 xx 2^6 = 64 xx 64`.

`-> x = 64 (64^64 = 2^2048)`.

1

`2^{x}:4=16`

`2^{x}=16.4`

`2^{x}=2^4 .2^2`

`2^{x}=2^6`

`x=6`

2^x : 4 = 16

2^x = 16 x 4

2^x = 64

2^x = 2⁶

x = 6

\(\left(x-1\right)^3=\dfrac{27}{8}\)

\(\Rightarrow x-1=\sqrt[3]{\dfrac{27}{8}}\)

\(\Rightarrow x-1=\dfrac{3}{2}\)

\(\Leftrightarrow x=\dfrac{5}{2}\)

(x-1)³ = 27/8

(x-1)³ = (3/2)³

x - 1 = 3/2

x = 3/2 + 1

x = 5/2

\(-4\dfrac{5}{7}.33\dfrac{1}{3}+4\dfrac{5}{7}.47\dfrac{1}{3}\)

\(=4\dfrac{5}{7}.\left(-33\dfrac{1}{3}+47\dfrac{1}{3}\right)\)

\(=4\dfrac{5}{7}.\left(-\dfrac{100}{3}+\dfrac{142}{3}\right)\)

\(=4\dfrac{5}{7}.14\)

\(=\dfrac{33}{7}.14\)

\(=66\)

   \(\dfrac{-33}{7}\).\(\dfrac{100}{3}\) + \(\dfrac{33}{7}\).\(\dfrac{142}{3}\)

= \(\dfrac{33}{7}\).\(\left(\dfrac{-100}{3}+\dfrac{142}{3}\right)\)

= \(\dfrac{33}{7}\).\(\dfrac{42}{3}\)

= 66

Lời giải:

a. Đề sai. Bạn xem lại

b. 

Diện tích xung quanh: $2.6.10+2.8.10=280$ (dm²)

Thể tích: $6.8.10=480$ (dm³)

c.

Diện tích xung quanh: $2.2A.A+2.A.A=6A^2$ (m²)

Thể tích: $2A.A.A=2A^3$ (m³)

a. \(\widehat{yOz}=\dfrac{\widehat{xOy}}{2}=\dfrac{60^0}{2}=30^0\)

b. \(\widehat{tOz}=\widehat{tOy}-\widehat{yOz}=180^0-30^0=150^0\)

Đs...

\(0,25x:3=\dfrac{5}{6}:0,125\\ \Rightarrow0,25x:3=\dfrac{5}{6}:\dfrac{1}{8}\\ \Rightarrow0,25x:3=\dfrac{20}{3}\\ \Rightarrow0,25x=\dfrac{20}{3}\times3\\ \Rightarrow0,25x=20\\ \Rightarrow x=20:0,25\\ \Rightarrow x=80\)

Vậy \(x=80\)

0,25x : 3 = \(\dfrac{20}{3}\)

0,25x = 20

x = \(\dfrac{20}{0,25}\)

x = 80

` 3/4 - 5/6x =2 - 2/3`

`<=> 3/4 -5/6x = 6/3 -2/3 = 4/3`

`<=> 5/6x = 3/4 -4/3 = -7/12`

`=> x = -7/12 : 5/6 = -7/10`

\(\dfrac{3}{4}-\dfrac{5}{6}x=2-\dfrac{2}{3}\)

\(\dfrac{3}{4}-\dfrac{5}{6}x=\dfrac{4}{3}\)

\(\dfrac{5}{6}x=\dfrac{3}{4}-\dfrac{4}{3}\)

\(\dfrac{5}{6}x=\dfrac{9}{12}-\dfrac{16}{12}\)

\(\dfrac{5}{6}x=\dfrac{-7}{12}\)

\(x=\dfrac{-7}{12}:\dfrac{5}{6}\)

\(x=\dfrac{-7}{12}:\dfrac{10}{12}\)

\(x=\dfrac{-7}{12}.\dfrac{12}{10}\)

\(x=\dfrac{-7}{10}\)