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Đề thi đánh giá năng lực
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bài 7
Thay x=3 và y=-1 ta có hệ
\(\hept{\begin{cases}6-a=b+4\\3a-b=8+9a\end{cases}\Leftrightarrow\hept{\begin{cases}a+b=2\\6a+b=-6\end{cases}\Leftrightarrow}\hept{\begin{cases}a=-\frac{8}{5}\\b=\frac{18}{5}\end{cases}}}\)
bài 8 cách làm tương tự nhé, ta thay x và y vào sẽ được hệ của a và b.
hỏi chấm??
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