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\(B=\left(\dfrac{1}{9}-\dfrac{5}{7}\right)+\dfrac{3}{6}+\left(\dfrac{-12}{17}+\dfrac{-1}{2}\right)+\dfrac{5}{9}.\)
\(B=\dfrac{1}{9}-\dfrac{5}{7}+\dfrac{1}{2}-\dfrac{12}{17}-\dfrac{1}{2}+\dfrac{5}{9}.\)
\(B=\left(\dfrac{1}{9}+\dfrac{5}{9}\right)-\dfrac{5}{7}-\dfrac{12}{17}+\left(\dfrac{1}{2}-\dfrac{1}{2}\right).\)
\(B=\dfrac{2}{3}-\dfrac{5}{7}-\dfrac{12}{17}=\dfrac{-269}{357}.\)
Lời giải:
a. Mẹ An mua thực phẩm hết số tiền là:
$3\times 120000+4\times 50000+20\times 3500+220000=850000$ (đồng)
b. Mẹ An mua thực phẩm và khẩu trang hết:
$850000+2\times 35000=920000$ (đồng)
c) \(\left(\dfrac{1}{2}\cdot x+\dfrac{1}{4}\right)\cdot\left(2x-\dfrac{1}{3}\right)=0\)
\(\dfrac{1}{2}\cdot x+\dfrac{1}{4}=0\)
\(\dfrac{1}{2}\cdot x=0-\dfrac{1}{4}\)
\(\dfrac{1}{2}\cdot x=-\dfrac{1}{4}\)
\(x=-\dfrac{1}{4}\div\dfrac{1}{2}\)
\(x=-\dfrac{1}{2}\)
\(2x-\dfrac{1}{3}=0\)
\(2x=0+\dfrac{1}{3}\)
\(2x=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}\div2\)
\(x=\dfrac{1}{6}\)
\(\Rightarrow\) \(x=\) {\(-\dfrac{1}{2};\dfrac{1}{6}\)}
\(S=\dfrac{2}{1\cdot4}+\dfrac{2}{4\cdot7}+\dfrac{2}{7\cdot10}+\dfrac{2}{10\cdot13}+\dfrac{2}{13\cdot16}+\dfrac{2}{16\cdot19}+\dfrac{2}{19\cdot22}\)
\(S=\dfrac{2\cdot1}{1\cdot4}+\dfrac{2\cdot1}{4\cdot7}+\dfrac{2\cdot1}{7\cdot10}+\dfrac{2\cdot1}{10\cdot13}+\dfrac{2\cdot1}{13\cdot16}+\dfrac{2\cdot1}{16\cdot19}+\dfrac{2\cdot1}{19\cdot22}\)
\(S=2\cdot\left(\dfrac{1}{1\cdot4}+\dfrac{1}{4\cdot7}+\dfrac{1}{7\cdot10}+\dfrac{1}{10\cdot13}+\dfrac{1}{13\cdot16}+\dfrac{1}{16\cdot19}+\dfrac{1}{19\cdot22}\right)\)
\(S=2\cdot\left(1-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{10}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{19}+\dfrac{1}{19}-\dfrac{1}{22}\right)\)
\(S=2\cdot\left(1-\dfrac{1}{22}\right)\)
\(S=2\cdot\dfrac{21}{22}\)
\(S=\dfrac{42}{22}\)
\(S=\dfrac{21}{11}\)
mí cái đáp án trên là mk tính bừa ra nên ko đúng thì bn thông cảm hen
\(B=\left(\dfrac{1}{9}-\dfrac{5}{7}\right)+\dfrac{3}{6}+\left(\dfrac{-12}{17}+\dfrac{-1}{2}\right)+\dfrac{5}{9}.\)
\(B=\dfrac{1}{9}-\dfrac{5}{7}+\dfrac{1}{2}-\dfrac{12}{17}-\dfrac{1}{2}+\dfrac{5}{9}=\left(\dfrac{1}{9}+\dfrac{5}{9}\right)+\left(\dfrac{1}{2}-\dfrac{1}{2}\right)-\dfrac{5}{7}-\dfrac{12}{17}=\dfrac{2}{3}-\dfrac{5}{7}-\dfrac{12}{17}=\dfrac{238-255-252}{357}=\dfrac{-269}{357}.\)